SOLUTION: Find the exact values of sin(2u), cos(2u), and tan(2u) using the double-angle formulas. csc(u) = 6, 0 < u < 𝜋/2 sin(2u) = cos(2u) = tan(2u) =

Algebra ->  Trigonometry-basics -> SOLUTION: Find the exact values of sin(2u), cos(2u), and tan(2u) using the double-angle formulas. csc(u) = 6, 0 < u < 𝜋/2 sin(2u) = cos(2u) = tan(2u) =      Log On


   



Question 1172165: Find the exact values of sin(2u), cos(2u), and tan(2u) using the double-angle formulas.
csc(u) = 6, 0 < u < 𝜋/2
sin(2u) =

cos(2u) =

tan(2u) =

Found 3 solutions by Boreal, MathTherapy, Alan3354:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
sin 2u=2 sin u cos u;
csc u =6, sin u =1/6, u=9.59 degrees
cos u has to be sqrt(35)/6
sin 2u=2 sqrt(35)/36=sqrt(35)/18
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cos (2u)=cos ^2 u-sin^2 u
=(35/36)-(1/36)=17/18
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tan 2u= sin 2u / cos 2u
=sqrt(35)/17
or 2 tan (u)/1-tan^2 (u)
where tan u = 1/sqrt(35)=sqrt(35)/35
so 2 sqrt(35)/35/1-35/35^2; the denominator is (35^2-35/35^2)
this will become 2 sqrt(35)*35/1190, and that is 2 sqrt(35)/34 or sqrt(35)/17), same as above. sin u/ cos u is easier, since those have already been obtained.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find the exact values of sin(2u), cos(2u), and tan(2u) using the double-angle formulas.
csc(u) = 6, 0 < u < 𝜋/2
sin(2u) =

cos(2u) =

tan(2u) =
With 0+%3C+u+%3C+pi%2F2, 0 is in the 1st quadrant



Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Half angle formulas on Wikipedia covers this very well.
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What is the point of having someone do them for you?