SOLUTION: The cross section of a window box planter is an isosceles trapezoid with an area of 96 inItem Editor Image. The bases of the cross section have lenghts of 10 in and 14 in. What

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The cross section of a window box planter is an isosceles trapezoid with an area of 96 inItem Editor Image. The bases of the cross section have lenghts of 10 in and 14 in. What       Log On

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Question 1171913: The cross section of a window box planter is an
isosceles trapezoid with an area of 96 inItem Editor Image. The
bases of the cross section have lenghts of 10 in
and 14 in. What is the height, in inches, of the
planter?

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
A=(1/2)h(b1+b2)
192=h(24)
h=8 in.