SOLUTION: An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 3048 feet and Plane B is at an altitude of 4500 feet. Plane A is gaining altitude at 60.5fe
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Question 1171841: An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 3048 feet and Plane B is at an altitude of 4500 feet. Plane A is gaining altitude at 60.5feet per second and Plane B is gaining altitude at 30.25 feet per second.
How many seconds will pass before the planes are at the same altitude?
What will their altitude be when they're at the same altitude?
please help, thank you! Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! altitude A=3048+60.5x, where x is in seconds.
altitude B=4500+30.25x
set them equal
3048+60.5x=4500+30.25x
30.25x=1452
x=48 seconds
the altitude will be 4500+30.25*48=5952 feet
