Question 117170: If a function is increasing at a rate of and the points (0,2) and (3,4) are both on the graph of f(x). What will be the y value when x is 3 if the rate is changed to and the point (0,2) remains on the new line.
Answer by Edwin McCravy(20056) (Show Source):
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If a function is increasing at a rate of and the points
(0,2) and (3,4) are both on the graph of f(x). What will be
the y value when x is 3 if the rate is changed to and
the point (0,2) remains on the new line.
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Here is what we must know in order to do the problem:
If the rate of change of a function is constant
then
#1. The function is a linear function of the form f(x) = mx + b.
and
#2. The slope m is the constant rate of change of the linear
function f(x).
and
#3. The ordered pair (0,b) is a zero of f(x) and is called the
y-intercept, as it is represented by the point on the graph
of f(x), which is a non-vertical straight line, where that
line crosses the y-axis.
Since we are told that:
>>"...a function is increasing at a rate of 2/3..."<<
we know by #2 above that m =
and since we are told that
>>"...(0,2)...[IS]...on the graph of f(x)"<<
we know by #3 above that b = 2
then by #1, we know the function is
f(x) = mx + b or
f(x) = x + 2
So we didn't need the information that (3,4) is on the line.
It was extra.
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>>"...the rate is changed to 4/3..."<<
Now we're going to change the rate (i.e,, the slope m from
to , so the new m = and since
>>"...the point (0,2) remains on the new line..."<<
We know that the new function, call it g(x), has b = 2, so
g(x) = mx + b
g(x) = x + 2
So we are asked:
>>"...What will be the [NEW] y value when x is 3..."<<
So we substitute 3 for x
g(x) = x + 2
g(3) = (3) + 2
g(3) = 4 + 2
g(3) = 6.
Since the y-value IS the function value, then the
final answer is 6.
Edwin
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