SOLUTION: An object is launched from ground level directly upward at a rate of 48 meters per second. The equation for the object’s height is y = -16x2 + 48x. What values of x is the objec
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Question 1171625: An object is launched from ground level directly upward at a rate of 48 meters per second. The equation for the object’s height is y = -16x2 + 48x. What values of x is the object at or above a height of 32 meters? Answer by ikleyn(52799) (Show Source):
To answer this question, solve equation
-16x2 + 48x = 32.
Cancel the common factor 16 to simplify
-x^2 + 3x = 2
x^2 - 3x + 2 = 0
(x-1)*(x-2) = 0.
The roots are x= 1 and x= 2.
So, an object will be at or above the height 0f 32 meters from x= 1 second to x= 2 seconds. ANSWER
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