SOLUTION: keats sells concessions at the rangers games. last week he sold $6,034.00 worth of food. he sells hot dogs for $6.50 and bags of popcorn for $4.25. If he sold 1,127 items that wee

Algebra ->  Equations -> SOLUTION: keats sells concessions at the rangers games. last week he sold $6,034.00 worth of food. he sells hot dogs for $6.50 and bags of popcorn for $4.25. If he sold 1,127 items that wee      Log On


   

Question 1171612: keats sells concessions at the rangers games. last week he sold $6,034.00 worth of food. he sells hot dogs for $6.50 and bags of popcorn for $4.25. If he sold 1,127 items that week, how may of each item did he sell?
Answer by ikleyn(52813) About Me  (Show Source):
You can put this solution on YOUR website!
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Let x = the number of hot dogs.

Then the number of bags = 1127-x.


Total money equation is


    6.50x + 4.25(1127-x) = 6034.


From the equation


    x = %286034+-+4.25%2A1127%29%2F%286.50-4.25%29 = 553.


ANSWER.  553 hot dogs, and the rest items,  1127-553 = 574 are bags of popcorn.


CHECK.  553*6.50 + 574*4.25 = 6034.00 dollars, total.  ! Precisely correct !

Solved.