SOLUTION: Paul left the airport traveling toward the ocean two hours before Arjun. Arjun traveled in the opposite direction going 10 km/h faster than Paul for two hours after which time they

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Paul left the airport traveling toward the ocean two hours before Arjun. Arjun traveled in the opposite direction going 10 km/h faster than Paul for two hours after which time they      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1171578: Paul left the airport traveling toward the ocean two hours before Arjun. Arjun traveled in the opposite direction going 10 km/h faster than Paul for two hours after which time they were 230 km apart. What was Paul’s speed?
Answer by ikleyn(52866) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let x be the Paul' speed, in km/h.

Then the Arjun' speed is  (x+10) km/h.


Paul's traveled distance is  (2+2)x = 4x kilometers.

Arjun's traveled distance is 2*(x+10) kilometers.


The total distance equation is

    4x + 2*(x+10) = 230  kilometers.


Simplify and solve

    4x + 2x + 20 = 230

    6x           = 230 - 20 = 210 

     x                      = 210/6 = 35.


ANSWER.   Paul' speed is  35 km/h.

Solved.

----------------

For simple Travel & Distance problems,  see introductory lessons
    - Travel and Distance problems
    - Travel and Distance problems for two bodies moving in opposite directions
    - Travel and Distance problems for two bodies moving in the same direction (catching up)
in this site.

They are written specially for you.

You will find the solutions of many similar problems there.

Read them and learn once and for all from these lessons on how to solve simple Travel and Distance problems.

Become an expert in this area.