SOLUTION: From Precious Mirror of the Four Elements ( 1303 A.D. ) . I take along a bottle with some wine in it for an excursion in the spring. On reaching a tavern, I double the bottle’s c

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Question 1171556: From Precious Mirror of the Four Elements ( 1303 A.D. ) . I take along a bottle with some wine in it for an excursion in the spring. On reaching a tavern, I double the bottle’s content and drink 1 9/10 dou in the tavern. After passing 4 taverns, the bottle is empty. How much wine was there at the beginning? Show your solutions.
Found 2 solutions by ankor@dixie-net.com, ikleyn:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
I take along a bottle with some wine in it for an excursion in the spring.
On reaching a tavern, I double the bottle’s content and drink 1 9/10 dou in the tavern.
After passing 4 taverns, the bottle is empty.
How much wine was there at the beginning? Show your solutions.
:
let x = the amt of wine originally
Assuming he drinks 1.9 d at each tavern
2x - 1.9 - 4(1.9) = 0
2x - 1.9 - 7.6 = 0
2x - 9.5 = 0
2x = 9.5
x = 9.5/2
x = 4.75 d originally

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
I take along a bottle with some wine in it for an excursion in the spring.
On reaching a tavern, I double the bottle’s content and drink 1 9/10 dou in the tavern.
After passing 4 taverns, the bottle is empty. How much wine was there at the beginning?
~~~~~~~~~~~~


            My interpretation of this problem is different from that of @ankor@dixie-net.com.

            THEREFORE,  my solution and my answer are different.


We have a sequence of numbers  x%5B0%5D, x%5B1%5D, x%5B2%5D, x%5B3%5D, x%5B4%5D.


x%5B0%5D is the amount of wine in the bottle originally.

x%5Bk%5D is the amount of wine in the bottle at the Exit     from the  k-th tavern 
                                (same as at the entering to   the (k+1)-th tavern), k = 1,2,3,4.


From the problem's condition, we have this recursive formula

    x%5Bk%2B1%5D = 2%2Ax%5Bk%5D-1.9,      (1)


which is the formal mathematical translation of the problem's description.


We are given that  x%5B4%5D = 0, and they want we find x%5B0%5D.


Surely, the problem should be solved in a backward manner.

For it, I express x%5Bk%5D from (1) in this way

    x%5Bk%5D = %28x%5Bk%2B1%5D%2B1.9%29%2F2    (2)


Now I will go step by step BACKWARD from  k= 3  with  x%5B4%5D = 0.


In order for to facilitate my calculations, I use MS Excel in my computer with implemented formula (2) in it.


It provides all calculations in seconds, giving me THIS Table below

    k         x%5Bk%5D

--------------------------

    4		0
    3		0.95
    2		1.425
    1		1.6625
    0		1.78125


So, the ANSWER is: the initial amount of wine in the bottle was  1.78125  units of the volume.

SOLVED.