SOLUTION: 3 consecutive odd integers has a sum of 117 what is the least of these integers
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Question 1171539
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3 consecutive odd integers has a sum of 117 what is the least of these integers
Answer by
greenestamps(13200)
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The middle of the three integers is the average of all three.
117/3 = 39
The integers are 37, 39, and 41.
If you need a formal algebraic solution....
let x = middle integer
then x-2 = smallest
and x+2 = largest
