SOLUTION: Mrs. Richey can sell 36 picture frames each month if she charges $18 each. She estimates that for each $3 increase in price, she will sell 3 fewer frames.
Step 1 of 2 : Find the
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-> SOLUTION: Mrs. Richey can sell 36 picture frames each month if she charges $18 each. She estimates that for each $3 increase in price, she will sell 3 fewer frames.
Step 1 of 2 : Find the
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Question 1171476: Mrs. Richey can sell 36 picture frames each month if she charges $18 each. She estimates that for each $3 increase in price, she will sell 3 fewer frames.
Step 1 of 2 : Find the price that will yield the maximum revenue.
You can put this solution on YOUR website! (18+3x)(36-3x)=revenue ,where x is the number of increases of $3 in price.
648+54x-9x^2=revenue
maximize when x=-b/2a=-54/-18 or 3
$27 is the price at maximum revenue
27 is the numbers of frames sold for maximum revenue.
The answer is $27, the maximum revenue is $729.
