SOLUTION: There are 9 players on a hockey team.
a) In how many ways can the players be arranged on the bench?
b) In how many ways can the starting line-up (5 players) be picked?
c) What i
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-> SOLUTION: There are 9 players on a hockey team.
a) In how many ways can the players be arranged on the bench?
b) In how many ways can the starting line-up (5 players) be picked?
c) What i
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Question 1170922: There are 9 players on a hockey team.
a) In how many ways can the players be arranged on the bench?
b) In how many ways can the starting line-up (5 players) be picked?
c) What is the probability that Teemu will be the centre and Adam will be right wing? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 9 ways for first, 8 for the second, ..., 1 way for the last.
this is 9! or 362,880 ways.
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9C5=126 ways. (9!/5!4!)=9*8*7*6/4!
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probability is (1/9) for a given player to be center * (1/8) for a player to be the right wing. The answer is 1/72.
