SOLUTION: Find the missing coordinate of P, using the fact that P lies on the unit circle in the given quadrant. Coordinates Quadrant P( , -5/7) IV

Algebra ->  Trigonometry-basics -> SOLUTION: Find the missing coordinate of P, using the fact that P lies on the unit circle in the given quadrant. Coordinates Quadrant P( , -5/7) IV       Log On


   

Question 1170876: Find the missing coordinate of P, using the fact that P lies on the unit circle in the given quadrant.
Coordinates Quadrant
P( , -5/7) IV
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.

The missed coordinate is the POSITIVE value of this square root


    sqrt%281-%28-5%2F7%29%5E2%29 = sqrt%28%2849-25%29%2F49%29 = sqrt%2824%29%2F7 = %282%2Asqrt%286%29%29%2F7 = 0.699854...  or simply 0.7 (rounded).    ANSWER

Solved, answered, explained and completed.



Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Coordinates ....|.... Quadrant
P(x , -5%2F7) ....|.... +IV

x%5E2+%2B+%28-5%2F7%29%5E2+=+1%5E2
x%5E2+%2B+25%2F49+=+1+
x%5E2+++=+1+-25%2F49
x%5E2+++=+24%2F49
x=+sqrt%2824%2F49%29.........The sign is "+" (plus) at sqrt operator, because the point is in Quadrant IV
x=%282sqrt%286%29%29%2F7+->exact solution
P(%282sqrt%286%29%29%2F7, -5%2F7)