SOLUTION: Find the value of k so that the line through the points (-2,3) and (6,k) has y-intercept 6.

Algebra ->  Finance -> SOLUTION: Find the value of k so that the line through the points (-2,3) and (6,k) has y-intercept 6.      Log On


   

Question 1170741: Find the value of k so that the line through the points (-2,3) and (6,k) has y-intercept 6.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the line through the points

(-2,3) and (6,k)
slope:
m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
m=%28k-3%29%2F%286%2B2%29
m=%28k-3%29%2F8.....eq.1
y-intercept b=6
use y-intercept point ->(0,6) and (-2,3) to find the slope
m=%283-6%29%2F%28-2-0%29
m=-3%2F-2
m=3%2F2.....eq.2
from eq.1 and eq.2 we have
%28k-3%29%2F8=3%2F2....solve for k
2%28k-3%29=3%2A8
%28k-3%29=24%2F2
k-3=12
k=15
so, (6,k)=(6,15)
y=%28%28k-3%29%2F8%29x%2B6
y=%28%2815-3%29%2F8%29x%2B6
y=%2812%2F8%29x%2B6
y=%283%2F2%29x%2B6