SOLUTION: Make n the subject of the equation: n^0.5/(n+1) < a

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Question 1170618: Make n the subject of the equation:
n^0.5/(n+1) < a
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
That's not an equation, it's an inequality.
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If it's an equation I will do it.
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n^0.5/(n+1) = a
n^0.5 = a*(n+1) = an + a
Square
n = a^2n^2 + 2a^2n + a^2
a^2n^2 + (2a^2-1)*n + a^2 = 0
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n+=+%281-2a%5E2%29%2F2a%5E2+%2B+sqrt%28%282a%5E2-1%29%5E2+-+4a%5E2%2Aa%5E4%29%2F2a%5E2
n+=+%281-2a%5E2%29%2F2a%5E2+-+sqrt%28%282a%5E2-1%29%5E2+-+4a%5E2%2Aa%5E4%29%2F2a%5E2