Question 1170613: Solve for x: x^2= 3x-5
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! the equation is x^2 = 3x - 5
subtrct 3x from both sides of the equation and add 5 to both sides of the equation to get:
x^2 - 3x + 5 = 0.
use the quadratic equation to solve this quadratic equation to get:
the roots are:
z = 1.5 + 1.6583123951777i or x = 1.5 - 1.6583123951777i
those are the roots of the equation, which are complex numbers that contain an imaginary part because the equation does not cross the line y = 0.
if the roots were real, the graph of the equation would have cross the x-axis.
the x-axis is when the value of y on the graph is equal to 0.
the quadratic equation solves for the roots, even if they are not real.
a complex number has a real part and an imaginary part.
the real part is a real number.
the imaginary part is a real number times the letter i.
the letter i represents the square root of (-1).
here's a reference on complex numbers.
https://www.mathsisfun.com/numbers/complex-numbers.html
there are many more references on the web.
just do a search for complex numbers.
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