Question 1170548: Hi
The ratio of henry's eggs to Ivan's to Nellie's was 3;5;10 respectively. When nellie gave 56 eggs to be shared between Henry and ivan she found that the 3 had the same number of eggs.
How many eggs did Nellie have left
Thanks
Answer by ikleyn(52873)   (Show Source):
You can put this solution on YOUR website! .
The ratio of Henry's eggs to Ivan's to Nellie's was 3;5;10 respectively. When Nellie gave 56 eggs to be shared
between Henry and ivan she found that the 3 had the same number of eggs.
How many eggs did Nellie have left
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Solution
They had initially/originally 3x, 5x and 10x eggs, where x is some (unknown) integer number.
In all, they had originally 3x + 5x + 10x = 18x eggs.
After exchange, they have equal number of eggs, equal to 18x/3 = 6x for everyone.
Hence, Henry obtained 6x-3x = 3x eggs; Ivan obtained 6x-5x = x eggs from Nellie.
We know that the sum 3x + x = 4x is equal to 56:
4x = 56.
Hence, x = 56/4 = 14 eggs.
ANSWER. Nellie has 6x = 6*14 = 84 eggs left.
Solved, answered, explained and completed.
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