SOLUTION: Find the four fourth roots of z=16(cos 4pi/3 + i sin 4pi/3) Write each root in standard form. Any and all help would be greatly appreciated. I don't know how to even start. Than

Algebra ->  Trigonometry-basics -> SOLUTION: Find the four fourth roots of z=16(cos 4pi/3 + i sin 4pi/3) Write each root in standard form. Any and all help would be greatly appreciated. I don't know how to even start. Than      Log On


   



Question 1170521: Find the four fourth roots of z=16(cos 4pi/3 + i sin 4pi/3) Write each root in standard form.
Any and all help would be greatly appreciated. I don't know how to even start. Thank you!

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Noting that a 2pi rotation doesn't change things, we can express z in polar form:



Now finding the four 4th roots is nearly trivial (4th root of 16 is 2, then just divide exponents by 4). You must let n=0,1,2, and 3 to get the four 4th roots:

n=0: = 2(0.5 + i*0.866) = highlight%281+%2B+i%2A1.732%29+
(or highlight%281%2Bi%2Asqrt%283%29%29+ if exact answer is needed)
NOTE that z%5B0%5D is also called the principal root

Now set n=1 to find the 2nd root
n=1:
That exponent works out to +5pi%2F6+:

= +highlight%28-1.732+%2B+i%2A1%29+


Let n=2 then n=3 to get the remaining two roots. You should get:
n=2: +z%5B2%5D+=+2%2A%28cos%28%284pi%29%2F3%29+%2B+i%2Asin%28%284pi%29%2F3%29%29%29+
n=3: +z%5B3%5D+=+2%2A%28cos%28%2811pi%29%2F6%29+%2B+i%2Asin%28%2811pi%29%2F6%29%29%29+