SOLUTION: Hi, may i know how to solve this question? thank you~
The first three terms of an arithmetic progression are 2 sin x, 3 cos x and (sin x + 2 cos x) respectively, where x is an acu
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-> SOLUTION: Hi, may i know how to solve this question? thank you~
The first three terms of an arithmetic progression are 2 sin x, 3 cos x and (sin x + 2 cos x) respectively, where x is an acu
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Question 1170519: Hi, may i know how to solve this question? thank you~
The first three terms of an arithmetic progression are 2 sin x, 3 cos x and (sin x + 2 cos x) respectively, where x is an acute angle. Show that tan x = 4/3. Hence, find the sum of the first twenty terms of the progression. [ Use tan x = 4/3 for sin x and cos x ] Answer by ikleyn(52790) (Show Source):
The characteristic property that three numbers , and form an Arithmetic progression is this equality
- = -
In our case, it means that
3cos(x) - 2sin(x) = (sin(x) + 2cos(x)) - 3cos(x).
Simplify it
3cos(x) - 2 cos(x) + 3cos(x) = sin(x) + 2sin(x)
4cos(x) = 3sin(x).
Divide both sides by cos(x). You will get
= , or
tan(x) = .
So, the first statement is proved.
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Next, if tan(x) = and the angle x is acute, then there is only one possibility:
the angle x is in QI, and sin(x) = = 0.8, cos(x) = = 0.6.
In this case, the 1st term of the AP is 2*0.8 = 1.6;
the 2nd term of the AP is 3*0.6 = 1.8 and
the common difference is 1.8 - 1.6 = 0.2.
Then the 20th term is 1.6+19*0.2 = 5.4 and
the sum of the first 20 terms is = 70.