SOLUTION: MARTIN LEAVES HOME AT 9 AM BICYCLING AT A RATE OF 24 MI/H. TWO HOURS LATER, JOHN LEAVES, DRIVING AT THE RATE OF 48 MI/H. AT WHAT TIME WILL JOHN CATCH UP WITH MARTIN?

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: MARTIN LEAVES HOME AT 9 AM BICYCLING AT A RATE OF 24 MI/H. TWO HOURS LATER, JOHN LEAVES, DRIVING AT THE RATE OF 48 MI/H. AT WHAT TIME WILL JOHN CATCH UP WITH MARTIN?      Log On

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Question 117049: MARTIN LEAVES HOME AT 9 AM BICYCLING AT A RATE OF 24 MI/H. TWO HOURS LATER, JOHN LEAVES, DRIVING AT THE RATE OF 48 MI/H. AT WHAT TIME WILL JOHN CATCH UP WITH MARTIN?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
24T=48(T-2)
24T=48T-96
24T-48T=-96
-24T=-96
T=-96/-24
T=4 HOURS AFTER MARTIN LEAVES THEY WILL MEET.
PROOF
24*4=48*2
96=96