Question 1170489: The number of accidents on a particular highway averages 4.4 per year. Assume that the number of accidents follows a Poisson distribution.
What is the probability that there are more than three accidents next year?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! probability of 0 1 2 3
for 0 e^(-4.4)
for 1, it is e^(-4.4)*4.4^1/1!
for 2 it is e^(-4.4)*4.4^2/2!
for 3 it is e^(-4.4)*4.4^3/6
These are 0.0123+0.0540+0.1188+0.1743=0.3594
the answer is the complement of that or 0.6406
also calculator 1-poissoncdf(4.4,3)ENTER=0.6406
the 1- is needed, because the calculator calculates left tail probability, and here we want the right tail.
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