SOLUTION: Given the equation of the parabola (x+2)^2=2(y-1), find the vertex, directrix, focus and length of the latus rectum. Sketch the graph.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Given the equation of the parabola (x+2)^2=2(y-1), find the vertex, directrix, focus and length of the latus rectum. Sketch the graph.      Log On


   

Question 1170326: Given the equation of the parabola (x+2)^2=2(y-1), find the vertex, directrix, focus and length of the latus rectum. Sketch the graph.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B2%29%5E2=2%28y-1%29


THIS, 2%28y-1%29=%28x%2B2%29%5E2
conforms to the format 4p%28y-k%29=%28x-h%29%5E2

4p=2
p=1%2F2


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Vertex, (-2,1)
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Focus, (-2,1.5)
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Directrix, y=1-1%2F2, or y=1%2F2
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