SOLUTION: The area of the rectangle shown is 2(3x-2)over x-1. Find the width? The length given is 2x + 6 over 12x -15. I know area = l x w but how do you find the width when the area i

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The area of the rectangle shown is 2(3x-2)over x-1. Find the width? The length given is 2x + 6 over 12x -15. I know area = l x w but how do you find the width when the area i      Log On


   

Question 117030This question is from textbook
: The area of the rectangle shown is 2(3x-2)over x-1. Find the width?
The length given is 2x + 6 over 12x -15.
I know area = l x w but how do you find the width when the area is given? This question is from textbook

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
A=LW ___ W=A/L