SOLUTION: The length of the floor is 32m longer than its width and there is more than 200 square meters. You will cover the floor completely with tiles. What will be the possible dimensions

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Question 1170293: The length of the floor is 32m longer than its width and there is more than 200 square meters. You will cover the floor completely with tiles. What will be the possible dimensions of the floor?
Found 3 solutions by josgarithmetic, Clanther, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
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width at least 29.25m
length at least 61.25m


-
w width;
w%28w%2B32%29%3E200
w%5E2%2B32w-200%3E0
.
.
w=%28-32%2Bsqrt%2832%5E2%2B4%2A200%29%29%2F2
w=29.25
.
.

Answer by Clanther(6) About Me  (Show Source):
You can put this solution on YOUR website!
let x be the width
Equation:
(32+x)x>200
x²+32x>200
To find the roots:
x²+32x-200=0
by completing the square:
x²+32x+256=200+256
(x+16)²=±√456
x=-16±21.35
Use the positive value of the factors since we are looking for measurement.
x=-16+21.35
x=5.35m width
length
32+5.35=37.35m
The possible dimensions are:
6m by 38m, 7m by 39m, 8m by 40m and so on...

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
The length of the floor is 32m longer than its width and there is more than 200 square meters. You will cover the floor completely with tiles. What will be the possible dimensions of the floor?
, so correct answer is Tutor @Clanther's.