SOLUTION: John rented a truck for one day. There was a base fee of $16.99, and there was an additional charge of 87 cents for each mile driven. John had to pay $215.35 when he returned the t

Algebra ->  Test -> SOLUTION: John rented a truck for one day. There was a base fee of $16.99, and there was an additional charge of 87 cents for each mile driven. John had to pay $215.35 when he returned the t      Log On


   

Question 1170258: John rented a truck for one day. There was a base fee of $16.99, and there was an additional charge of 87 cents for each mile driven. John had to pay $215.35 when he returned the truck. For how many miles did he drive the truck?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
c = 16.99 + .87 * m
c is the total cost.
m is the number of miles.

when c = 215.35, the equation becomes 215.35 = 16.99 + .87 * m
subtract 16.99 from both sides of this equation to get 215.35 - 16.99 = .87 * m
combine like terms to get 198.36 = .87 * m
solve for m to get m = 198.36 / .87 = 228.

he drove the truck for 228 miles.
the total cost was 16.99 + .87 * 228 = 215.35.

all the numbers check out.
your solution is that he drove 228 miles.