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Question 1170245:  1.a) Deduce that the total surface area S of a cylinder closed at both ends with height, H and base radius R is given by: S=2πR(R+H) where π is a constant. 
b) Find the volume of S given that H =15.0m and R =5.0m (leaving your answer in terms of π) 
c) Calculate the amount of water the tank can hold leaving your answer in terms of π. 
d) Calculate the height (h) of a cuboid tank of cross-sectional area 25 metre cube which has the same capacity as the cylinder tank in (c) above.
 
 
 
 Found 2 solutions by  CPhill, ikleyn: Answer by CPhill(1987)      (Show Source): 
You can  put this solution on YOUR website! Let's break down this problem step by step.
 
**1.a) Deduce the Total Surface Area of a Closed Cylinder**
 
* **Area of the Top and Bottom Circles:** Each circle has an area of πR². Since there are two circles (top and bottom), their combined area is 2πR². 
* **Lateral Surface Area (Curved Surface):** Imagine unrolling the side of the cylinder. This forms a rectangle with height H and width equal to the circumference of the base (2πR). Therefore, the lateral surface area is 2πRH. 
* **Total Surface Area (S):** To find the total surface area, add the areas of the top, bottom, and lateral surfaces: 
    S = 2πR² + 2πRH 
    S = 2πR(R + H)
 
**1.b) Find the Volume of the Cylinder**
 
* **Volume Formula:** The volume (V) of a cylinder is given by V = πR²H. 
* **Given Values:** H = 15.0 m and R = 5.0 m. 
* **Calculation:** 
    V = π(5.0 m)²(15.0 m) 
    V = π(25 m²)(15.0 m) 
    V = 375π m³
 
**1.c) Calculate the Amount of Water the Tank Can Hold**
 
The amount of water the tank can hold is equal to its volume.
 
* **Answer:** The tank can hold 375π m³ of water.
 
**1.d) Calculate the Height of a Cuboid Tank with the Same Capacity**
 
* **Cuboid Volume Formula:** The volume of a cuboid is given by V = Area of base × height. 
* **Given Information:** 
    * Volume of the cuboid = Volume of the cylinder = 375π m³ 
    * Cross-sectional area (base area) of the cuboid = 25 m² 
* **Calculation:** 
    375π m³ = 25 m² × h 
    h = (375π m³) / (25 m²) 
    h = 15π m
 
**Answers:**
 
a)  S = 2πR(R + H) 
b)  V = 375π m³ 
c)  375π m³ 
d)  h = 15π m 
 
 Answer by ikleyn(52903)      (Show Source): 
You can  put this solution on YOUR website! .
 
 
In your post,  in the last question,  you write
 
 
        ". . . cross-sectional area 25 metre cube . . . ".
 
 
 
Dear missis or mister writer,  the area is  NEVER  measures in  "metre cube ".  
 
 
The appropriate unit for the area is  " square meter ". 
 
 
 
As I noticed from your posts, you make this error systematically.
 
 
 
It tells me a lot about mathematical qualification of a person who created this problem.
 
 
 
 
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