SOLUTION: a tour bus leaves sacramento every friday evening at 6:00 pm for a 270 mile trip to las vegas. due to mechanical problems the bus will be leaving at 6:30 pm today. to arrive in veg
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Question 1170197: a tour bus leaves sacramento every friday evening at 6:00 pm for a 270 mile trip to las vegas. due to mechanical problems the bus will be leaving at 6:30 pm today. to arrive in vegas at the same time, the driver must go 6 mph faster than usual. what is the buses normal speed ? Found 3 solutions by Boreal, ikleyn, MathTherapy:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! normal speed of bus is 270mi/x where x is number of hours
speed of bus leaving at 6:30 and distance is 270 miles, so speed is 270/x-0.5.
(270/x)+6=270/(x-0.5)
(270+6x)/x=270/(x-0.5)
270x=270x-135+6x^2-3x
0=6x^2-3x-135
0=(x-5)(6x+27)
x=5 hours only positive root
54 mph is normal speed (270/5)
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when the bus goes 60 mph, it takes 4.5 hours,
You can put this solution on YOUR website!
a tour bus leaves sacramento every friday evening at 6:00 pm for a 270 mile trip to las vegas. due to mechanical problems the bus will be leaving at 6:30 pm today. to arrive in vegas at the same time, the driver must go 6 mph faster than usual. what is the buses normal speed ?
Let normal speed be S
Then faster speed is: S + 6
We then get the following TIME equation:
270S(2) + S(S + 6) = 270(2)(S + 6) ------- Multiplying by LCD, 2S(S + 6)
(S - 54)(S + 60) = 0
Normal speed, or
