SOLUTION: The polynomial of degree 4, P ( x ) has a root of multiplicity 2 at x = 3 and roots of multiplicity 1 at x = 0 and x = − 2 . It goes through the point ( 5 , 56 ) . Find a formula
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-> SOLUTION: The polynomial of degree 4, P ( x ) has a root of multiplicity 2 at x = 3 and roots of multiplicity 1 at x = 0 and x = − 2 . It goes through the point ( 5 , 56 ) . Find a formula
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Question 1170149: The polynomial of degree 4, P ( x ) has a root of multiplicity 2 at x = 3 and roots of multiplicity 1 at x = 0 and x = − 2 . It goes through the point ( 5 , 56 ) . Find a formula for P ( x ) .
P(x)= Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! The equation for P(x) with the form P(x) = a*x(x-3)^2(x+2), will have roots
at x=0, x=-2 and a double root at x=3. Now we need to find the parameter a
from the point (5,56).
P(5) = a(5)(2)^2(7) = 140a = 56
Thus a = 56/140 = 0.4
Ans: P(x) = 0.4x(x+2)(x-3)^2
