Question 1169660: A jar containing at least 10 candies and chocolates whose worth must be more than Php 30.00. Each candy costs Php 1.00 while each chocolate costs php 2.00. How many combinations of candies and chocolates are placed in the jar?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52800)   (Show Source):
You can put this solution on YOUR website! .
It is not a Math problem.
It is a (very bad style) puzzle, where the reader should guess the meaning of the words that he (or she) sees in the post.
Avoid posting such gibberish to this forum.
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If I see such . . . posted to the forum next time, I will delete it momentarily to avoid unnecessary discussions.
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For some reasons (even don't know why), I always thought that people from Philippine have -- in mass --
more accurate mathematical thinking than average American students.
Simply I assumed that their mathematical school education is better than the US math education.
But, probably, the contemporary progress makes Math education uniformly bad in all countries . . .
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
The wording of the problem is indeed awkward; but that can be excused because the "Php" (Philippines pesos) suggests that English is not the first language of the author of the problem.
But ignoring the awkward presentation of the problem, the problem itself makes little sense.
For one thing, the problem says that the number of candies and chocolates must be at least 10 and the total cost of them is at least Php 30. But there is no way to make a total cost of Php 30 or more with fewer than 10 candies and chocolates, when the most expensive item costs Php 2. So the requirement of at least 10 candies and chocolates is superfluous.
Then, with the total cost of the candies and chocolates having to be MORE THAN Php30, there are obviously an infinite number of combinations of candies and chocolates that could be in the jar. So the question that is asked is nonsense.
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