SOLUTION: the red rose theater sells tickets for $4.50 and $6.00. a total of 380 tickets were sold for their last performance of"mickey the mouse". if the sales for the performance totaled $

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: the red rose theater sells tickets for $4.50 and $6.00. a total of 380 tickets were sold for their last performance of"mickey the mouse". if the sales for the performance totaled $      Log On

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Question 1169592: the red rose theater sells tickets for $4.50 and $6.00. a total of 380 tickets were sold for their last performance of"mickey the mouse". if the sales for the performance totaled $1972.50, how many tickets were sold at each price?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
x of lower priced
y of higher priced
system%284.5x%2B6y=1972.50%2Cx%2By=380%29


An option for trying Elimination Method is to divide the money equation, both sides, by 1.5 to simplify.
system%283x%2B4y=1315%2Cx%2By=380%29
And then most easy from there, multiply the ticket count equation by 3:

system%283x%2B4y=1315%2C3x%2B3y=1140%29
Now, E1-E2 gives you
highlight%28y=175%29, and you can find x on your own.

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

the red rose theater sells tickets for $4.50 and $6.00. a total of 380 tickets were sold for their last performance of"mickey the mouse". if the sales for the performance totaled $1972.50, how many tickets were sold at each price?
Let number of $4.50 tickets sold, be C

Then number of $6 tickets sold = 380 - C

We then get: 4.5C + 6(380 - C) = 1,972.5

4.5C + 2,280 - 6C = 1,972.5

4.5C - 6C = 1,972.5 - 2,280

- 1.5C = - 307.5

Number of $4.50 tickets sold, or 

You should now be able to find the number of $6 tickets that were sold!