SOLUTION: A smoke detector system uses two devices, A and B. Suppose the probability that it will be detected by device A is 0.95, the probability that it will be detected by device B is 0.9

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Question 1169426: A smoke detector system uses two devices, A and B. Suppose the probability that it will be detected by device A is 0.95, the probability that it will be detected by device B is 0.90, and the probability that it will be detected by both devices is 0.89. What is the probability of the event that the smoke will be detected by device B alone? Express the question in notation and compute.
Answer by ikleyn(52864) About Me  (Show Source):
You can put this solution on YOUR website!
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    P(B alone) = P(B) - P(B and A) = 0.9 - 0.89 = 0.01.    ANSWER

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