SOLUTION: A square and a rectangle have the same area. The length of the rectangle is 9 inches more than twice the length of the side of the square. The width of the rectangle is 6 inches le

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: A square and a rectangle have the same area. The length of the rectangle is 9 inches more than twice the length of the side of the square. The width of the rectangle is 6 inches le      Log On


   

Question 1169319: A square and a rectangle have the same area. The length of the rectangle is 9 inches more than twice the length of the side of the square. The width of the rectangle is 6 inches less than the side of the square.
What is the value of x?

Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52897) About Me  (Show Source):
You can put this solution on YOUR website!
.

Who is   " x " ?



Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
If side length of the square, x
Then rectangle dimensions 2x+9 and x-6

Because areas of the two figures given as equal,
x%5E2=%282x%2B9%29%28x-6%29
.
.
.
x%5E2-3x-54=0
%28x-9%29%28x%2B6%29=0
highlight%28x=9%29


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You need to define your x before asking about it.