SOLUTION: Two cyclists are on an oval track of 2 kilometers perimeter and start at the same time, but in
the opposite direction. If one of them advances at a speed of 12 km / h and the othe
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-> SOLUTION: Two cyclists are on an oval track of 2 kilometers perimeter and start at the same time, but in
the opposite direction. If one of them advances at a speed of 12 km / h and the othe
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Question 1169291: Two cyclists are on an oval track of 2 kilometers perimeter and start at the same time, but in
the opposite direction. If one of them advances at a speed of 12 km / h and the other at a
speed of 8 km / h, After how long will they meet each other? And how far has each of them
from their original starting point?
Since they are going in opposite directions, their speeds are additive. 12 + 8 = 20. So they are approaching each other at 20 km/hr. Since it is a 2 km track, it takes 1/10 of an hour to complete a circuit at 20 km/hr. 1/10 hour is 6 minutes. So they will meet in 6 minutes, and the faster one will have traveled 12 km/hr times 1/10 hour - 1.2 km and the slower one will have traveled 8 km/hr times 1/10 hour - 0.8 km.
John
My calculator said it, I believe it, that settles it
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