SOLUTION: A very large jug of x litres of orange squash is 10% concentrate(the rest water). When 5 litres of concentrate is added the jug is now 12% concentrate A. Form an equation in term

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A very large jug of x litres of orange squash is 10% concentrate(the rest water). When 5 litres of concentrate is added the jug is now 12% concentrate A. Form an equation in term      Log On


   

Question 1169274: A very large jug of x litres of orange squash is 10% concentrate(the rest water). When 5 litres of concentrate is added the jug is now 12% concentrate
A. Form an equation in terms of X( by considering the amount of concentrate we have).
B Hence determine X
please solve this
Regards
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
x liters of 10% concentrate was mixed with 5 liters of an unknown p percent concentrate, and the result mixture was 12% concentrate.

%280.10x%2B%28p%2F100%29%2A5%29%2F%28x%2B5%29=0.12

You can solve for x if you want to but you still have the unknown p % concentrate which was added to form the mixture.

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

A very large jug of x litres of orange squash is 10% concentrate(the rest water). When 5 litres of concentrate is added the jug is now 12% concentrate
A. Form an equation in terms of X( by considering the amount of concentrate we have).
B Hence determine X
please solve this
Regards
.1x + 5 = .12(x + 5)

.1x + 5 = .12x + .6

.1x - .12x = .6 - 5

- .02x = - 4.4