SOLUTION: If logx^2=a and logy^3=b and logxy=c where x>0,y>0, show that 6c =3a+2b

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Question 1169200: If logx^2=a and logy^3=b and logxy=c where x>0,y>0, show that
6c =3a+2b
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
Using the rules of logarithms, a = 2logx -> logx = a/2, b = 3logy -> logy=b/3,
and logx + logy = c.
Thus a/2 + b/3 = c -> 6c = 3a + 2b