SOLUTION: Kevin is now four times as old as mark. Five years ago, The sum of their ages was 45. How old are they now? (Hint:k=44)

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Question 1169117: Kevin is now four times as old as mark. Five years ago,
The sum of their ages was 45. How old are they now? (Hint:k=44)
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let Kevin's age be K and Mark's age M
given:
Kevin is now four times as old as Mark:
K=4M ....eq.1
Five years ago, Kevin was K-5 years old and Mark was M-5
and, the sum of their ages was 45: so we have
%28K-5%29%2B%28M-5%29=45
K-5%2BM-5=45
K%2BM-10=45
K%2BM=45%2B10
K%2BM=55........solve for K
K=55-M.....eq.2
from eq.1 and eq.2 we have
4M=55-M
4M%2BM=55
5M=55
M=11

go to:
K=4M ....eq.1, substitute M
K=4%2A11
K=44
so, Kevin is 44 and Mark is 11


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Kevin is now four times as old as mark. Five years ago,
The sum of their ages was 45. How old are they now? (Hint:k=44)
Let Mark's age be M

Then Kevin's is: 4M

We then get: M + 4M - 2(5) = 45

5M = 55

Mark, or 

Now you can find Kevin's age!