Question 1169085: Again, need help before midnight. Thankyou for all your help!
Cherie went to a Virginia Tech football game and spent $20.50 on a hotdog, drink, and some nachos. The drink was twice as much as the hotdog and the nachos was $2.50 more than three times the hotdog. How much did each item cost?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source):
You can put this solution on YOUR website! h hotdog price
d drink price
n nachos price
(nachos was $2.50 more than three times the hotdog.)
Going along the description literally you have  ;
If you are careful, this can be turned into a single equation in just one unknown variable.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! Again, need help before midnight. Thankyou for all your help!
Cherie went to a Virginia Tech football game and spent $20.50 on a hotdog, drink, and some nachos. The drink was twice as much as the hotdog and the nachos was $2.50 more than three times the hotdog. How much did each item cost?
Let cost of the hotdog be H
Then cost of drink = 2H, and cost of nachos = 3H + 2.50
With total cost being $20.50, we get: H + 2H + 3H + 2.5 = 20.5
6H = 18
Cost of the hotdog, or 
Do you now think you can find the cost of the drink and the nachos?
FYI: The other person's answers are WRONG!! BEWARE!!!
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