SOLUTION: Good day. May you please assist me in the following question: The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary's age was 3 years m

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Question 1169065: Good day. May you please assist me in the following question:
The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary's age was 3 years more than twice Jane's age. Determine their current ages.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
This looks like an exercise already solved yesterday or the day before.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Good day. May you please assist me in the following question:
The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary's age was 3 years more than twice Jane's age. Determine their current ages.
Let Mary's age be M

Then Jane's is: 24 - M

Four years ago, Mary was M - 4, and Jane's was: 24 - M - 4, or 20 - M

We then get:  3(M - 4) = 2(20 - M) + 3

3M - 12 = 40 - 2M + 3

3M + 2M = 55

5M = 55

Mary or 

Now, find Jane's age!