SOLUTION: A jet takes 5 hours to travel a distance of 3800 miles against the wind. The return trip takes 4 hours with the wind. What is the rate of the jet in still air and what is the rate
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Question 1168919: A jet takes 5 hours to travel a distance of 3800 miles against the wind. The return trip takes 4 hours with the wind. What is the rate of the jet in still air and what is the rate of the wind? Answer by ikleyn(52798) (Show Source):
Let u be the plane speed at no wind.
Let v be the speed of the wind.
The effective speed of the plane with the wind is
u + v = = 760 mph. (1)
The effective speed of the plane against the wind is
u - v = = 950 mph. (2)
From equations (1) and (2), the speed of the plane at no wind is = 855 mph.
Then from equation (1), the speed of the wind is 855-760 = 95 mph.
Solved.
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It is a typical "tailwind and headwind" word problem.
