SOLUTION: A picture has a height that is 5/3 it's width. It is to be enlarged to have an area of 346 square inches. What will be the dimention of the enlargement?

Algebra ->  Length-and-distance -> SOLUTION: A picture has a height that is 5/3 it's width. It is to be enlarged to have an area of 346 square inches. What will be the dimention of the enlargement?       Log On


   



Question 1168908: A picture has a height that is 5/3 it's width. It is to be enlarged to have an area of 346 square inches. What will be the dimention of the enlargement?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x(5/3)x=346
(5/3)x^2=346
multiply both sides by 3/5
x^2=207.6
x=14.41 in=width
(5/3)x=24.01 in=height