| 
 
 
| Question 1168716:  If we roll a die two times, determine whether the following pairs of events are independent or dependent?
 a. Event A is rolling a 4 on the first die. Event B is rolling a 5 on the second die.
 b. Event A is rolling a 3 on the first die. Event B is getting the sum of more than 6 with the two dice.
 Found 2 solutions by  solver91311, Boreal:
 Answer by solver91311(24713)
      (Show Source): Answer by Boreal(15235)
      (Show Source): 
You can put this solution on YOUR website! These are independent probability of each is (1/6), probability of both is 1/36. Also, what happens on first roll has no bearing upon the second roll. 
 The second isn't clear.  If a is one roll and b is a different roll with BOTH die, then they are independent.
 If, however, a is the first roll, then b is a roll of the other die, and the two are added, then this is a dependent case, since the roll in the first case has direct bearing upon the sum in the second case.  If it is a 3, then the second die need to be 4,5,6.  If the first were a 1, then the second would have to be a 6.
 (1/6)(1/2)=(1/3), since the second die has to be 4,5,6.
 separately, they are (1/6) and (21/36) or (7/12), and that product is 7/72.
 | 
  
 | 
 |