SOLUTION: In the early 1960s, radioactive strontium-90 was released during atmospheric testing of nuclear weapons and got into the bones of people alive at the time. If the half-life of stro
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Question 1168675: In the early 1960s, radioactive strontium-90 was released during atmospheric testing of nuclear weapons and got into the bones of people alive at the time. If the half-life of strontium-90 is 27 years, what fraction of the strontium-90 absorbed in 1965 remained in people's bones in 1994? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! A=Aoe^(-kt)
0.5A=(Ao)e^(-27k)
0.5=e^-27k
ln both sides
-0.693=-27k
k=0.02567
t=29
-kt=-0.7445
Ao*e^(-0.7445)=0.4750Ao or 47.50%
