SOLUTION: Solve equation: xy = 600 (x + 10) (y - 5) = 600 xy - 5x + 10y - 50 = 600 Not sure how to solve.

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Question 1168628: Solve equation:
xy = 600
(x + 10) (y - 5) = 600
xy - 5x + 10y - 50 = 600
Not sure how to solve.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
To form your exercise better, solve the system of equations:
system%28xy=600%2C%28x%2B10%29%28y-5%29=600%29

Simplifying the second equation:
xy%2B10y-5x-50=600
and by substitute using the first equation,
600%2B10y-5x-50=600
10y-5x-50=0
2y-x-10=0
and if subtitute for x then
2y-600%2Fy-10=0

Continuing from that last equation, multiply left and right sides by y.
y%282y-600%2Fy-10%29=y%2A0
2y%5E2-600-10y=0
2y%5E2-10y=600
y%5E2-5y=300

And if you try to avoid solving a quadratic equation;
and then
y%28y-5%29=300
the factorization suggests highlight%28y=20%29.
You can evaluate x.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Solve equation:
xy = 600
(x + 10) (y - 5) = 600
xy - 5x + 10y - 50 = 600
Not sure how to solve.
matrix%281%2C3%2C+xy%2C+%22=%22%2C+600%29
matrix%281%2C6%2C+x%2C+%22=%22%2C+600%2Fy%2C+%22------%22%2C+eq%2C+%22%28i%29%22%29


(x + 10)(y  -  5) = 600 ------ eq (ii)
matrix%281%2C3%2C+%28600%2Fy+%2B+10%29%28y++-++5%29%2C+%22=%22%2C+600%29 ------- Substituting 600%2Fy for x in eq (ii)

matrix%281%2C3%2C+10y%5E2++-++%223%2C000%22++-++50y%2C+%22=%22%2C+0%29 ------- Multiplying by LCD, y

(y  -  20)(y + 15) = 0
y  -  20 = 0					OR					y + 15 = 0
y = 20						OR 					y = - 15


matrix%281%2C3%2C+x%2C+%22=%22%2C+600%2F20%29 ------- Substituting 20 for y in eq (i) 
x = 30



matrix%281%2C3%2C+x%2C+%22=%22%2C+600%2F%28-+15%29%29 ------- Substituting - 15 for y in eq (i) 
x = - 40