SOLUTION: Of the people who fished at Clearwater Park today, 21 had a fishing license, and 9 did not. Of the people who fished at Mountain View Park today, 18 had a license, and 2 did not. (

Algebra ->  Probability-and-statistics -> SOLUTION: Of the people who fished at Clearwater Park today, 21 had a fishing license, and 9 did not. Of the people who fished at Mountain View Park today, 18 had a license, and 2 did not. (      Log On


   

Question 1168563: Of the people who fished at Clearwater Park today, 21 had a fishing license, and 9 did not. Of the people who fished at Mountain View Park today, 18 had a license, and 2 did not. (No one fished at both parks.)Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license?
Do not round your answer.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
did not have a license is 9/30 from the first
had a license from the second is 18/20
and means probabilities are multiplied here.
3/10*9/10=27/100