SOLUTION: How many 6 in. x 6 in. tiles would be needed to cover a floor that is 96 square feet?

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Question 116805: How many 6 in. x 6 in. tiles would be needed to cover a floor that is 96 square feet?
Found 2 solutions by Fombitz, mdfetterman:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Each tile takes up 6x6=36 square inches.
The entire floor is 96 square feet.
In terms of square inches, it would be 96 sq.ft x 12 in/ft x 12 in/ft=13824 square inches.
If we divide the total area by the are of one tile, we can find how many tiles are needed.
N=13824%2F96=144
144 tiles are needed to cover the floor.

Answer by mdfetterman(2) About Me  (Show Source):
You can put this solution on YOUR website!
I believe Fombitz is a little off.
Yes each tile takes up 36 square inches.
Also Yes the floor is 13824 square inches,
However 144 tiles x 36 square inches per tile = 5184 square inches of coverage
should be
N=%2813824%29%2F%2836%29=384
So, 384 tiles are required to cover the floor