SOLUTION: Find the horizontal and vertical asymptotes of the following. Type “none” if the function does not have an asymptote. g(x)= 5x/x-1 Answer: Horizontal: Vertical:

Algebra ->  Functions -> SOLUTION: Find the horizontal and vertical asymptotes of the following. Type “none” if the function does not have an asymptote. g(x)= 5x/x-1 Answer: Horizontal: Vertical:       Log On


   



Question 116803: Find the horizontal and vertical asymptotes of the following. Type “none” if the function does not have an asymptote.
g(x)= 5x/x-1
Answer:
Horizontal:
Vertical:

Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Horizontal: y = 5x/x = 5
Vertical: x-1=0
x = 1
=================
Cheers,
Stan H.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The horizontal asymptote tells you, roughly, where the graph will go when x is really, really big.
When the degrees of the numerator and the denominator are the same, then the horizontal asymptote is found by dividing the leading terms, so the asymptote is given by:
y = (numerator's leading coefficient) / (denominator's leading coefficient)
This is always+true.

g%28x%29=+5x%2F%28x-1%29………… this function has degree-1 polynomials top and bottom; the degrees are the same in the numerator and the denominator
Since the degrees are the same, the numerator and denominator "pull" evenly; this graph should not drag down to the x-axis, nor should it shoot off to infinity.
Again, think in terms of big values for x.

When x is really big, you'll have, roughly, 5 times something big divided by once something big (minus a 1) so you'll roughly have
%285x%2Fx%29, which reduces to just 5

so, +horizontal+asymptote for this is +y+=+5
lim+x--> infinity...+5x+%2F%28x-1%29 -->+5
lim+x-->-infinity...+5x+%2F+%28x+-1%29+ -->+5

Vertical+asymptotes correspond to the zeroes of the denominator of a rational function.
So, set the denominator of the above fraction equal to zero and solve, this will tell me the values that x cannot be:
x-1+=+0
x+=+1………..so, x cannot be 1, because then I'd be dividing by zero
If you graph it, you will see how the graph avoid the line x+=+1