Question 1168027: The weight, F, of a body on the moon varies inversely as the square of the distance, d,
from the center of the moon. If a person weighs 60 pounds when they are 500 miles from
the center of the moon, how much would they weigh at a distance of 1000 miles from the
center of the moon?
Found 3 solutions by Boreal, josgarithmetic, ikleyn:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! F=k/d^2
60=k/500^2
k=15,000,000
use that in second part
F=15,000,000/1000^2
=15 pounds
60 pounds at 500 miles
double the distance and it is 1/2^2 for the weight.
Answer by josgarithmetic(39630)  (Show Source):
Answer by ikleyn(52879)  (Show Source):
You can put this solution on YOUR website! .
For your info (and for the info to other respectful tutors)
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The radius of the moon is 1,079.4 miles.
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So, it is a big question - - - what does it mean to be at the distance of 500 or 1000 miles from the center of the moon.
By the way, if the body is located deeply inside of the moon, then the statement of the problem about "proportionality" is
a) WRONG and b) INCORRECT.
My salutation to this person, illiterate in both Physics and Astronomy, who created this post (!)
To learn about the moon, read from this link
https://en.wikipedia.org/wiki/Moon
To learn about the Newton's gravitation law, read from this link
https://en.wikipedia.org/wiki/Newton%27s_law_of_universal_gravitation
(especially about Bodies with spatial extent).
Come to this forum again to learn something new (!)
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