SOLUTION: consider the function: f(x)= x^2+6x-2. Find h, the x-coordinate of the vertex of this parabola.

Algebra ->  Graphs -> SOLUTION: consider the function: f(x)= x^2+6x-2. Find h, the x-coordinate of the vertex of this parabola.      Log On


   



Question 116801: consider the function: f(x)= x^2+6x-2. Find h, the x-coordinate of the vertex of this parabola.
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
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f%28x%29=+x%5E2%2B6x-2
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This function is of the standard form:
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y+=+ax%5E2+%2B+bx+%2B+c
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Recall the quadratic formula that says for a function of this form the solutions for x are:
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x+=+-b%2F%282%2Aa%29+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%2F%282%2Aa%29+
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The first term on the right side (that is -b%2F%282%2Aa%29 will give you the value for x
at the vertex of the parabolic graph for y+=+ax%5E2+%2B+bx+%2B+c
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Comparing the given function with the standard form you can see that a in the standard form
[the multiplier of the x%5E2] is +1 in the given problem, and b in the standard form
[the multiplier of the x] is +6 in the given problem, and c (which we don't need) in
the standard function is -2 in the given problem.
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All you now have to do to solve this problem is plug the values for a and b into -b%2F%282%2Aa%29
and you get that the value of x at the vertex is:
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-b%2F%282%2Aa%29+=+-%28%2B6%29%2F%282%2A1%29+=+-6%2F2+=+-3
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So the answer to your problem is h = -3
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Here's the graph of the equation y+=+x%5E2+%2B+6x+-2 (shown in red) to help you validate
the answer. The green line is a vertical line through the vertex. It shows you that the
vertex has -3 as the value for its x:
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graph%28400%2C400%2C-10%2C5%2C-15%2C5%2Cx%5E2+%2B6x+-2%2C3000%28x%2B3%29%2F3%29
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Hope this helps you to understand the problem a little better.
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