SOLUTION: Find the additive and multiplicative inverses of the following complex number. (7, _9)

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Question 1167993: Find the additive and multiplicative inverses of the following complex number.
(7, _9)

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
I don't understand the underscore before 9 in "(7,_9)"? Did you mean (7,9)? or
(7,-9)?  I'll assume the "_" was a typo and you meant (7,9).  

Apparently you are using the ordered pair notation for complex numbers, which
is usually used at the beginning of a complex analysis course. 

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The definition of addition is (a,b)+(c,d) = (a+c,b+d) which is equivalent to

(a+bi)+(c+di) = (a+c)+(b+d)i

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In ordered pair notation, the additive inverse of (7,9) is (-7,-9). That's
because (7,9) + (-7,-9) = (0,0), the additive identity.

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The definition of multiplication is (a,b)(c,d) = (ac-bd,ad+bc) which is
equivalent to

(a+bi)(c+di) = ac+adi+bci+bdi2 = ac+(ad+bc)i+bd(-1) = (ac-bd)+(ad+bc)i

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In order pair notation, we find the multiplicative inverse of (7,9) by
letting it be (u,v), then

(7,9)(u,v) = (7u-9v,7v+9u) = (1,0), the multiplicative identity.  Then we have
the system of equations

system%287u-9v+=+1%2C9u%2B7v=0%29 which gives (u,v) = (7/130,-9/130)

Checking:

%28matrix%281%2C3%2C7%5E%22%22%5E%22%22%2C%22%2C%22%2C9%5E%22%22%29%29%28matrix%281%2C3%2C7%2F130%2C%22%2C%22%2C-9%2F130%29%29 = 

 =

 = %28matrix%281%2C3%2C130%2F130%2C%22%2C%22%2C0%2F130%29%29 = %28matrix%281%2C3%2C1%2C%22%2C%22%2C0%29%29

Edwin