Question 11679: If the mean and the standard deviation of a continuous random variable that is normally distributed are 26 and 6, find the interval that contains 95% of the distributions.
Answer by khwang(438) (Show Source):
You can put this solution on YOUR website! Assume the 95% interval is (mu -x,mu+x) where mu is the mean
We have x/6 = 1.96 [ this value corresponding to 0.95 from the Table]
so, x = 1.96*6 = 11.76
Hence,the solution interval is (26- 11.76,26+11.76)
= (14.24, 37.76)
Kenny
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