SOLUTION: A restaurant has a lunch special that allows you to chose 1 meat and 1 vegetable for $2.99. You order a food from the restaurant above and tell them to pick any meat and vegetable.
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-> SOLUTION: A restaurant has a lunch special that allows you to chose 1 meat and 1 vegetable for $2.99. You order a food from the restaurant above and tell them to pick any meat and vegetable.
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Question 1167766: A restaurant has a lunch special that allows you to chose 1 meat and 1 vegetable for $2.99. You order a food from the restaurant above and tell them to pick any meat and vegetable.
(1) How many ways can you select a meat and then a vegetable from roast, fish, or chicken; and then peas, beans, or squash.
(2) What is the probability that they pick your favorite meal of chicken and beans? Answer by ikleyn(52803) (Show Source):
(1) Three options for meat and three independent options for vegetable.
In all, 3 * 3 = 9 different outcomes are possible.
(the fundamental counting principle).
(2) Your favorite combination is one specific of 9 possible.
The probability is .
